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keith
Joined: 19 Sep 2005
Posts: 3355
Location: near Detroit, Michigan, USA
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 Posted: Fri Apr 09, 2010 2:39 pm Post subject: Free Press Apr 09, 2010 |
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| Code: | Puzzle: FP040910
+-------+-------+-------+
| . . 6 | 8 . 3 | 5 . . |
| . 4 . | . 2 5 | . 7 . |
| 2 . . | . . . | . . . |
+-------+-------+-------+
| 9 6 . | . . . | . . 3 |
| . . 3 | 6 . 1 | 4 . . |
| 7 . . | . . . | . 1 6 |
+-------+-------+-------+
| . . . | . . . | . . 7 |
| . 3 . | 7 1 . | . 9 . |
| . . 7 | 9 . 4 | 3 . . |
+-------+-------+-------+
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Keith |
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keith
Joined: 19 Sep 2005
Posts: 3355
Location: near Detroit, Michigan, USA
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| Posted: Fri Apr 09, 2010 6:23 pm Post subject: |
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After basics: | Code: | +----------------+----------------+----------------+
| 1 7 6 | 8 9 3 | 5 24 24 |
| 3 4 9 | 1 2 5 | 6 7 8 |
| 2 58 58 | 4 6 7 | 9 3 1 |
+----------------+----------------+----------------+
| 9 6 1 | 25 4 28 | 7 58 3 |
| 58 2 3 | 6 7 1 | 4 58 9 |
| 7 58 4 | 35 358 9 | 2 1 6 |
+----------------+----------------+----------------+
| 4568 9 258 | 235 358 268 | 1 46 7 |
| 456 3 25 | 7 1 26 | 8 9 45 |
| 568 1 7 | 9 58 4 | 3 26 25 |
+----------------+----------------+----------------+ |
Keith
Last edited by keith on Fri Apr 09, 2010 9:24 pm; edited 1 time in total |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Fri Apr 09, 2010 8:51 pm Post subject: |
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| I used a rather long simple coloring chain on 8 and a Type1 UR on 35. |
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keith
Joined: 19 Sep 2005
Posts: 3355
Location: near Detroit, Michigan, USA
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| Posted: Fri Apr 09, 2010 9:32 pm Post subject: |
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SS8 R69 solves R5C1 as 5.
46 W-wing solves it by removing 4 in R7C1.
Keith |
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tlanglet
Joined: 17 Oct 2007
Posts: 2468
Location: Northern California Foothills
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| Posted: Fri Apr 09, 2010 11:28 pm Post subject: |
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Two steps here also.
HP26[(26)r78c6 = (8)r7c6]r78c6 - r7c13 = r9c1 - (8=5)r5c1 - r6c2 = r6c45 - (5=2)r4c4; r4c6<>2
Type 1 UR 35 r67c45 forces r7c5=8
Ted |
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daj95376
Joined: 23 Aug 2008
Posts: 3854
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| Posted: Sat Apr 10, 2010 1:23 am Post subject: |
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| keith wrote: | After basics: | Code: | +----------------+----------------+----------------+
| 1 7 6 | 8 9 3 | 5 24 24 |
| 3 4 9 | 1 2 5 | 6 7 8 |
| 2 58 58 | 4 6 7 | 9 3 1 |
+----------------+----------------+----------------+
| 9 6 1 | 25 4 28 | 7 58 3 |
| 58 2 3 | 6 7 1 | 4 58 9 |
| 7 58 4 | 35 358 9 | 2 1 6 |
+----------------+----------------+----------------+
| 4568 9 258 | 235 358 268 | 1 46 7 |
| 456 3 25 | 7 1 26 | 8 9 45 |
| 568 1 7 | 9 58 4 | 3 26 25 |
+----------------+----------------+----------------+ |
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<35> UR in r67c45 implies r67c5=8 or r7c4=2
r67c5=8 => r9c5<>8
r7c4=2, r8c6=6, r7c6=8 => r9c5<>8
Singles follow. |
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keith
Joined: 19 Sep 2005
Posts: 3355
Location: near Detroit, Michigan, USA
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| Posted: Sat Apr 10, 2010 1:40 am Post subject: |
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Danny,
That's pretty sweet, isn't it!
In the solution I posted, I decided to stay away from Uniqueness arguments. Not that there's anything wrong with that (Seinfeld). 
Keith |
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daj95376
Joined: 23 Aug 2008
Posts: 3854
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| Posted: Sat Apr 10, 2010 4:55 am Post subject: |
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| keith wrote: | Danny,
That's pretty sweet, isn't it!
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Yes 
It's particularly impressive because I found it myself and not my solver.
I can still recall the time I encountered your post on URs ... and I could not get the principle through my thick skull. Now, I have a solver that catches many UR patterns ... just not the one I found here.
Regards, Danny |
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