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Vanhegan fiendish July 29, 2012

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arkietech

Joined: 31 Jul 2008
Posts: 1834
Location: Northwest Arkansas USA

Posted: Mon Jul 30, 2012 5:42 am Post subject: Vanhegan fiendish July 29, 2012

Code:

*-----------*
|..4|.8.|35.|
|6..|..5|...|
|...|42.|..8|
|---+---+---|
|.2.|.9.|.36|
|.9.|5.7|.8.|
|13.|.6.|.4.|
|---+---+---|
|2..|.43|...|
|...|8..|..9|
|.48|.5.|6..|
*-----------*

tlanglet

Joined: 17 Oct 2007
Posts: 2468
Location: Northern California Foothills

Posted: Mon Jul 30, 2012 1:26 pm Post subject:

Code after basics:

Code:

*-----------------------------------------------------------*
| 79 17 4 | 67 8 169 | 3 5 2 |
| 6 8 2 | 3 17 5 | 17 9 4 |
| 35 157 139 | 4 2 19 | 17 6 8 |
|-------------------+-------------------+-------------------|
| 8 2 7 | 1 9 4 | 5 3 6 |
| 4 9 6 | 5 3 7 | 2 8 1 |
| 1 3 5 | 2 6 8 | 9 4 7 |
|-------------------+-------------------+-------------------|
| 2 167 19 | 679 4 3 | 8 17 5 |
| 35 1567 13 | 8 17 126 | 4 127 9 |
| 79 4 8 | 79 5 12 | 6 12 3 |
*-----------------------------------------------------------*

A couple of solutions are

AUR(12)r89c68[(7)r8c8=(6)r8c6]-r7c4=(6-7)r1c4=7r2c5; -7r8c5

and

anp(79=6)r97c4-(6=2)r8c6-(2=7)r8c8-r8c5=r2c5; -7r1c4

Ted

arkietech

Joined: 31 Jul 2008
Posts: 1834
Location: Northwest Arkansas USA

Posted: Mon Jul 30, 2012 2:33 pm Post subject:

tlanglet wrote:

A couple of solutions are

AUR(12)r89c68[(7)r8c8=(6)r8c6]-r7c4=(6-7)r1c4=7r2c5; -7r8c5

and

anp(79=6)r97c4-(6=2)r8c6-(2=7)r8c8-r8c5=r2c5; -7r1c4

Nice!

Luke451

Joined: 20 Apr 2008
Posts: 310
Location: Southern Northern California

Posted: Mon Jul 30, 2012 3:47 pm Post subject:

tlanglet wrote:

Code after basics:

Code:

A couple of solutions are

AUR(12)r89c68[(7)r8c8=(6)r8c6]-r7c4=(6-7)r1c4=7r2c5; -7r8c5

and

anp(79=6)r97c4-(6=2)r8c6-(2=7)r8c8-r8c5=r2c5; -7r1c4

Ted

Dig the UR, lost on the anp.
Why not just (79=6)r97c4-UR[(6)r8c6=(7)r8c8] ==>r8c5<>7

Marty R.

Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA

Posted: Mon Jul 30, 2012 4:35 pm Post subject:

tlanglet wrote:

Code after basics:

Code:

A couple of solutions are

AUR(12)r89c68[(7)r8c8=(6)r8c6]-r7c4=(6-7)r1c4=7r2c5; -7r8c5

and

anp(79=6)r97c4-(6=2)r8c6-(2=7)r8c8-r8c5=r2c5; -7r1c4

Ted

I also used the 12 UR to create pincers on 7; r8c5<>7.

tlanglet

Joined: 17 Oct 2007
Posts: 2468
Location: Northern California Foothills

Posted: Mon Jul 30, 2012 5:17 pm Post subject:

Luke451 wrote:

tlanglet wrote:

Code after basics:

Code:

A couple of solutions are

AUR(12)r89c68[(7)r8c8=(6)r8c6]-r7c4=(6-7)r1c4=7r2c5; -7r8c5

and

anp(79=6)r97c4-(6=2)r8c6-(2=7)r8c8-r8c5=r2c5; -7r1c4

Ted

Dig the UR, lost on the anp.
Why not just (79=6)r97c4-UR[(6)r8c6=(7)r8c8] ==>r8c5<>7

Because I am BLIND ! Embarassed

Many times in the past I have realized I used a long and/or a messy path instead of an obvious simple path.

Thanks for the comment.........

Ted

Luke451

Joined: 20 Apr 2008
Posts: 310
Location: Southern Northern California

Posted: Mon Jul 30, 2012 5:48 pm Post subject:

tlanglet wrote:

Many times in the past I have realized I used a long and/or a messy path instead of an obvious simple path.

Don't I know. It's also much easier to be the kibitzer than the content provider!

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