| View previous topic :: View next topic |
| Author |
Message |
peterj
Joined: 26 Mar 2010
Posts: 974
Location: London, UK
|
 Posted: Wed Dec 08, 2010 6:13 pm Post subject: Krampus Edition - "?" #1 |
 |
|
| Code: | *-----------*
|.6.|94.|...|
|...|..2|3..|
|132|...|..4|
|---+---+---|
|...|1..|8..|
|3..|...|..2|
|..5|..7|...|
|---+---+---|
|2..|...|463|
|..8|2..|...|
|...|.59|.7.|
*-----------* |
| Code: | | 060940000000002300132000004000100800300000002005007000200000463008200000000059070 |
(c) Helmut Saueregger |
|
| Back to top |
|
 |
storm_norm
Joined: 18 Oct 2007
Posts: 1741
|
| Posted: Thu Dec 09, 2010 7:55 am Post subject: |
|
|
| Code: | +---------------+-----------------+-----------------+
| 8 6 7 | 9 4 3 | 15 2 15 |
| 5 9 4 | 7(6) 1 2 | 3 8 7(6) |
| 1 3 2 | 5678 678 568 | (67) 9 4 |
+---------------+-----------------+-----------------+
| 479 247 6 | 1 29 45 | 8 3 579 |
| 3 48(7) 1 | 4568 689 4568 | 59(7) 45 2 |
| 49 28 5 | 3 28 7 | 169 14 169 |
+---------------+-----------------+-----------------+
| 2 5 9 | 78 78 1 | 4 6 3 |
| 467 (47) 8 | 2 3 6-4 | 159 15 159 |
| 6-4 1 3 | (46) 5 9 | 2 7 8 |
+---------------+-----------------+-----------------+ |
#1...(4=6)r9c4 - (6)r2c4 = (6)r2c9 - (6=7)r3c7 - (7)r5c8 = (7)r5c2 - (7=4)r8c2;
r9c1 <> 4
r8c6 <> 4
| Code: | +---------------+------------------+------------------+
| 8 6 7 | 9 4 3 | 15 2 15 |
| 5 9 4 | 67 1 2 | 3 8 67 |
| 1 3 2 | 5678 67-8 (58) | 67 9 4 |
+---------------+------------------+------------------+
| 47(9) 247 6 | 1 (29) 4(5) | 8 3 79(5) |
| 3 478 1 | 568 689 45-8 | 579 4(5) 2 |
| (49) 28 5 | 3 (28) 7 | 169 (14) 169 |
+---------------+------------------+------------------+
| 2 5 9 | 78 78 1 | 4 6 3 |
| 47 47 8 | 2 3 6 | 159 (15) 159 |
| 6 1 3 | 4 5 9 | 2 7 8 |
+---------------+------------------+------------------+ |
#2...(8=2)R6C5 - (2=9)R4C5 - (9)R4C1 = (9-4)R6C1 = (4-1)R6C8 = (1-5)R8C8 = (5)R5C8 - (5)R4C9 = (5)R4C6 - (5=8)R3C6;
R3C5 <> 8
R5C6 <> 8
| Code: | +--------------+--------------+---------------+
| 8 6 7 | 9 4 3 | 15 2 15 |
| 5 9 4 | 67 1 2 | 3 8 67 |
| 1 3 2 | 5 6-7 8 | 6(7) 9 4 |
+--------------+--------------+---------------+
| 479 247 6 | 1 29 45 | 8 3 579 |
| 3 (78) 1 | 68 689 45 | 9(7) 45 2 |
| 49 2(8) 5 | 3 2(8) 7 | 169 14 169 |
+--------------+--------------+---------------+
| 2 5 9 | 78 (78) 1 | 4 6 3 |
| 47 47 8 | 2 3 6 | 159 15 159 |
| 6 1 3 | 4 5 9 | 2 7 8 |
+--------------+--------------+---------------+ |
#3... (7=8)R7C5 - (8)R6C5 = (8)R6C2 - (8=7)R5C2 - (7)R5C7 = (7)R3C7; R3C5 <> 7 |
|
| Back to top |
|
|
peterj
Joined: 26 Mar 2010
Posts: 974
Location: London, UK
|
| Posted: Thu Dec 09, 2010 2:42 pm Post subject: |
|
|
A lucky find on an m-wing with an ANT instead of bivalue...
| Code: | *-------------------------------------------------------------*
| 8 6 7 | 9 4 3 | (15) 2 15 |
| 5 9 4 | 67 1 2 | 3 8 67 |
| 1 3 2 | 5678 (6)78 568 | 7-6 9 4 |
|-------------------+---------------------+-------------------|
| 479 247 6 | 1 29 45 | 8 3 579 |
| 3 478 1 | 4568 (6)8(9) 4568 | 57(9) 45 2 |
| 49 28 5 | 3 28 7 | (169) 14 169 |
|-------------------+---------------------+-------------------|
| 2 5 9 | 78 78 1 | 4 6 3 |
| 467 47 8 | 2 3 46 | (159) 15 159 |
| 46 1 3 | 46 5 9 | 2 7 8 |
*-------------------------------------------------------------*
ANT(6=159)r168c7 - (9)r5c7=(9-6)r5c5=r3c5 ; r3c7<>6 |
|
|
| Back to top |
|
|
daj95376
Joined: 23 Aug 2008
Posts: 3854
|
| Posted: Thu Dec 09, 2010 7:12 pm Post subject: |
|
|
Peter, you came thiiiissss close to catching ronk's pattern for an L3-Wing: X=6, Y=9, Z=7
| Code: | L2-Wing: (X)a = (X)b - (X)c = (X-Y)d = (Y)e "a" and "e" in same house; a<>Y, e<>X
L3-Wing: (X)a = (X - Y)b = (Y-Z)c = (Z)d "a" and "d" in same house; a<>Y, d<>X
|
I stumbled across it while reviewing the chains listed by my solver.
(I don't have it specifically programmed into my MWSL-Wing finder program.)
Regards, Danny |
|
| Back to top |
|
|
peterj
Joined: 26 Mar 2010
Posts: 974
Location: London, UK
|
| Posted: Thu Dec 09, 2010 8:19 pm Post subject: |
|
|
| daj95376 wrote: | | Peter, you came thiiiissss close to catching ronk's pattern for an L3-Wing |
Well, I can see it now you point it out!
My head is still looking for two candidate m-wing like patterns and then I scavenge around for a bivalue, then a "pseudocell"/short xy-chain then an ALS - in order to create the A=B strong link to finish it off!
Looking for a strong-link on a third candidate will have to be next on the checklist! |
|
| Back to top |
|
|
daj95376
Joined: 23 Aug 2008
Posts: 3854
|
| Posted: Thu Dec 09, 2010 8:52 pm Post subject: |
|
|
Peter, I'm terrible at finding patterns ... let alone chains. That's why I wrote my solver -- to have it show me the simple chains that I'd never find on my own.
That said, wait until you see the ridiculous solution that I'm about to post for "?" #2. |
|
| Back to top |
|
|
tlanglet
Joined: 17 Oct 2007
Posts: 2468
Location: Northern California Foothills
|
| Posted: Fri Dec 10, 2010 3:40 am Post subject: |
|
|
| Code: | *-----------------------------------------------------------*
| 8 6 7 | 9 4 3 | 15 2 15 |
| 5 9 4 | 67 1 2 | 3 8 67 |
| 1 3 2 | 5678 678 568 | 67 9 4 |
|-------------------+-------------------+-------------------|
| 479 247 6 | 1 29 d45 | 8 3 579 |
| 3 478 1 | 4568 689 d4568 | 579 45 2 |
| 49 28 5 | 3 28 7 | 169 14 169 |
|-------------------+-------------------+-------------------|
| 2 5 9 | 78 78 1 | 4 6 3 |
| 467 47 8 | 2 3 c46 | 159 15 159 |
|a46 1 3 |b46 5 9 | 2 7 8 |
*-----------------------------------------------------------* |
I need help to describe this move. I started looking at a possible m-wing in abcd: (4=6)r9c1-r9c4=(6-4)r8c6=(4)r45c6. Thus either r4c6=4 or r5c6=4, which act as a pincer with (4)r9c1.
I then extended the beginning of the chain: (4)r9c1-r6c1=r6c8-(4=5)r5c8-r5c46=(5)r4c6 which forces r5c6=4
How do I combine these two steps into an AIC that is meaningful?
Ted
P. S. A BUG+2 that forces r5c4=6 is needed to complete the puzzle. |
|
| Back to top |
|
|
daj95376
Joined: 23 Aug 2008
Posts: 3854
|
| Posted: Fri Dec 10, 2010 5:17 am Post subject: |
|
|
| tlanglet wrote: | | Code: | *-----------------------------------------------------------*
| 8 6 7 | 9 4 3 | 15 2 15 |
| 5 9 4 | 67 1 2 | 3 8 67 |
| 1 3 2 | 5678 678 568 | 67 9 4 |
|-------------------+-------------------+-------------------|
| 479 247 6 | 1 29 d45 | 8 3 579 |
| 3 478 1 | 4568 689 d4568 | 579 45 2 |
| 49 28 5 | 3 28 7 | 169 14 169 |
|-------------------+-------------------+-------------------|
| 2 5 9 | 78 78 1 | 4 6 3 |
| 467 47 8 | 2 3 c46 | 159 15 159 |
|a46 1 3 |b46 5 9 | 2 7 8 |
*-----------------------------------------------------------* |
I need help to describe this move. I started looking at a possible m-wing in abcd: (4=6)r9c1-r9c4=(6-4)r8c6=(4)r45c6. Thus either r4c6=4 or r5c6=4, which act as a pincer with (4)r9c1.
I then extended the beginning of the chain: (4)r9c1-r6c1=r6c8-(4=5)r5c8-r5c46=(5)r4c6 which forces r5c6=4
How do I combine these two steps into an AIC that is meaningful?
|
I don't agree with the part in red above. If I were to join your chains into a single AIC, the logic would boil down to:
if r4c6=4 then ( r4c6=4 or r5c6=4) -- which is meaningless.
The wrinkle in your logic is that the extension forces r5c6=4 or r5c4=4. |
|
| Back to top |
|
|
tlanglet
Joined: 17 Oct 2007
Posts: 2468
Location: Northern California Foothills
|
| Posted: Fri Dec 10, 2010 1:26 pm Post subject: |
|
|
Danny,
I wondered about the validity of my conclusion, but convinced myself it was OK. Maybe next time I will get it correct.................
Ted |
|
| Back to top |
|
|
|
FAQ
Search
Memberlist
Usergroups
Register
Profile
Log in to check your private messages
Log in
