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		Clement
 
 
  Joined: 24 Apr 2006 Posts: 1113 Location: Dar es Salaam Tanzania
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				 Posted: Fri Oct 15, 2010 6:24 pm    Post subject: Free Press Oct 15, 2010 | 
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				| A kite in 7 originating from BOX 5 eliminating 7 in r8c9 leads to BUG 1 which solves it. | 
			 
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		tlanglet
 
 
  Joined: 17 Oct 2007 Posts: 2468 Location: Northern California Foothills
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				 Posted: Sat Oct 16, 2010 1:36 pm    Post subject: Re: Free Press Oct 15, 2010 | 
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				 	  | Clement wrote: | 	 		  | A kite in 7 originating from BOX 5 eliminating 7 in r8c9 leads to BUG 1 which solves it. | 	  
 
 
Clement,
 
 
Please post your puzzle so others may work it also.
 
 
Ted | 
			 
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		keith
 
 
  Joined: 19 Sep 2005 Posts: 3355 Location: near Detroit, Michigan, USA
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				 Posted: Sat Oct 16, 2010 2:09 pm    Post subject:  | 
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				Here is the puzzle:
 
 	  | Code: | 	 		  Puzzle: FP101510
 
+-------+-------+-------+
 
| . . 6 | . . . | . . 2 |
 
| . . . | . 1 . | 3 7 4 |
 
| 2 . . | . . 4 | . . 1 |
 
+-------+-------+-------+
 
| . . . | 9 . 1 | . . . |
 
| . 2 3 | . . . | 6 . . |
 
| . . . | 6 2 3 | . . . |
 
+-------+-------+-------+
 
| 8 . . | 5 . . | . . 3 |
 
| 5 9 1 | . 6 . | . . . |
 
| . . . | . . . | 9 . . |
 
+-------+-------+-------+
 
 | 	  
 
Play this puzzle online at the Daily Sudoku site
 
Keith | 
			 
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		keith
 
 
  Joined: 19 Sep 2005 Posts: 3355 Location: near Detroit, Michigan, USA
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				 Posted: Sat Oct 16, 2010 2:58 pm    Post subject:  | 
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				After basics: 	  | Code: | 	 		  +-------------+-------------+-------------+
 
| 4   1   6   | 7   3   5   | 8   9   2   | 
 
| 9   58  58  | 2   1   6   | 3   7   4   | 
 
| 2   3   7   | 8   9   4   | 5   6   1   | 
 
+-------------+-------------+-------------+
 
| 6   4   58  | 9   78d 1   | 2   3   578 | 
 
|1-7  2   3   | 4   5   78e | 6   18  9   | 
 
| 17a 58  9   | 6   2   3   | 147 148 578 | 
 
+-------------+-------------+-------------+
 
| 8   6   24  | 5   47c 9   | 17b 12  3   | 
 
| 5   9   1   | 3   6   27  | 47  248 78  | 
 
| 3   7   24  | 1   48  28  | 9   5   6   | 
 
+-------------+-------------+-------------+ | 	  
 
 	  | Quote: | 	 		  | M-wing:  1 in a forces 1 in b.  ac are pincers in 7.  Extend pincer c to e, removing 7 in R5C1. | 	  
 
 
Keith | 
			 
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		tlanglet
 
 
  Joined: 17 Oct 2007 Posts: 2468 Location: Northern California Foothills
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				 Posted: Sat Oct 16, 2010 3:03 pm    Post subject:  | 
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				The code after basics:
 
 	  | Code: | 	 		  *--------------------------------------------------*
 
 | 4    1    6    | 7    3    5    | 8    9    2    |
 
 | 9   *58  *58   | 2    1    6    | 3    7    4    |
 
 | 2    3    7    | 8    9    4    | 5    6    1    |
 
 |----------------+----------------+----------------|
 
 | 6    4   *58   | 9    78   1    | 2    3   *578  |
 
 | 17   2    3    | 4    5    78   | 6    18   9    |
 
 | 17  *58   9    | 6    2    3    | 14-7 148 *578  |
 
 |----------------+----------------+----------------|
 
 | 8    6    24   | 5    47   9    | 17   12   3    |
 
 | 5    9    1    | 3    6    27   | 47   248  -78  |
 
 | 3    7    24   | 1    48   28   | 9    5    6    |
 
 *--------------------------------------------------* | 	  
 
Notice the  6-cell Type 2 UR(58)r246c239 marked *; r6c7,r8c9<>7
 
This was a fun, unusual more but it did not solve the puzzle, so we need a
 
 
BUG+1; r6c8=1 | 
			 
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