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nataraj
Joined: 03 Aug 2007
Posts: 1048
Location: near Vienna, Austria
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 Posted: Sun Nov 23, 2008 7:30 pm Post subject: Competition Diabolical #1232 Nov 23 |
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| Code: |
+-----------+-----------+-----------+
| . 2 . | . . . | 1 9 . |
| . . . | 9 . 6 | . . . |
| 5 . . | . . . | . . 8 |
+-----------+-----------+-----------+
| . . 6 | . 7 . | . 1 3 |
| . 4 . | . . . | . 2 . |
| 8 9 . | . 3 . | 5 . . |
+-----------+-----------+-----------+
| 3 . . | . . . | . . 7 |
| 9 . . | . . 5 | . . . |
| . 6 2 | . . . | . 3 . |
+-----------+-----------+-----------+
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play online
Hint: There is a generalized m-wing
(1)r9c1=r6c3 (using SL (4) in row 2); r5c1<>1 |
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storm_norm
Joined: 18 Oct 2007
Posts: 1741
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| Posted: Mon Nov 24, 2008 8:07 pm Post subject: |
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| Code: | .---------------------.---------------------.---------------------.
| 6 2 78 | 578 58 3 | 1 9 4 |
| 147 1378 1478 | 9 18 6 | 37 5 2 |
| 5 137 9 | 1247 124 1247 | 367 67 8 |
:---------------------+---------------------+---------------------:
| 2 5 6 | 48 7 9 | 48 1 3 |
| 17 4 3 | 56 56 18 | 78 2 9 |
| 8 9 17 | 124 3 124 | 5 47 6 |
:---------------------+---------------------+---------------------:
| 3 18 5 | 1246 12469 124 | 2469 468 7 |
| 9 78 478 | 3 246 5 | 246 468 1 |
| 14 6 2 | 1478 1489 1478 | 49 3 5 |
'---------------------'---------------------'---------------------' |
| Quote: | (1=4)r9c1 - (4)r8c3 = (4-1)r2c3 = (1)r2c1; r5c1 <> 1
nice one nataraj. a one stepper! |
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re'born
Joined: 28 Oct 2007
Posts: 80
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| Posted: Tue Nov 25, 2008 4:15 am Post subject: |
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| storm_norm wrote: |
| Quote: | (1=4)r9c1 - (4)r8c3 = (4-1)r2c3 = (1)r2c1; r5c1 <> 1
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Would you explain your last link:
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storm_norm
Joined: 18 Oct 2007
Posts: 1741
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| Posted: Tue Nov 25, 2008 6:35 am Post subject: |
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| re'born wrote: | | storm_norm wrote: |
| Quote: | (1=4)r9c1 - (4)r8c3 = (4-1)r2c3 = (1)r2c1; r5c1 <> 1
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Would you explain your last link:
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oh my, that is not looking good. I think I had that backwards.
should be (1=4)r9c1- (4)r2c1 = (4-1)r2c3 = (1)r6c3; r5c1 <> 1
or it could be (1=4)r9c1 - (4)r8c3 = (4-1)r2c3 = (1)r6c3; r5c1 <>1
thanx, Re'born |
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re'born
Joined: 28 Oct 2007
Posts: 80
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| Posted: Tue Nov 25, 2008 2:22 pm Post subject: |
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| storm_norm wrote: |
oh my, that is not looking good. I think I had that backwards.
should be (1=4)r9c1- (4)r2c1 = (4-1)r2c3 = (1)r6c3; r5c1 <> 1
or it could be (1=4)r9c1 - (4)r8c3 = (4-1)r2c3 = (1)r6c3; r5c1 <>1
thanx, Re'born |
Ah, thank you. I should have seen it after your first 'chain'. Very elegant solution. |
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